(x^2+1)^2+2(x^2+1)-35=0

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Solution for (x^2+1)^2+2(x^2+1)-35=0 equation: 



(x^2+1)^2+2(x^2+1)-35=0

We multiply parentheses

2x^2+(x^2+1)^2+2-35=0

We add all the numbers together, and all the variables

2x^2+(x^2+1)^2-33=0

We move all terms containing x to the left, all other terms to the right

2x^2+(x^2+1)^2=33

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